Earth Density as a Function of Radius

By Da_Alyssa104 09 May, 2022 Post a Comment

Distance on the surface of the earth then the spherical earth equation would be φ λ φ dE R cos d dN R d where R is the radius of the sphere and the angle differences are in radians. This value is equal to 5520 kilograms per cubic meter.

Density As A Function Of Radius In T He Earth S Mantle 22 Download Scientific Diagram

Calculate CMR2 for the equal thickness model in c above.

. And the Earths volume is a function of its radius. A linear interpolation is used between grid points with allowance for possible discontinuities in terms of normalized radius. Where R is the radius of the planet ρ is the density M is the mass of the planet and r is your distance from the center.

4 3 V 4 r 3 sphere S. What is the gfs at the surface of a planet of density 2p and radius 2R. If the earth were of lead of average density 1 1 3 1 0 3 k g m 3 what would be the value of acceleration due to gravity on the surface.

Mass 10 24 kg 59722 Volume 10 10 km 3 108321 Equatorial radius km 6378137 Polar radius km 6356752 Volumetric mean radius km 6371000 Core radius km 3485 Ellipticity Flattening 0003353 Mean density kgm 3 5513 Surface gravity ms 2 9798 Surface acceleration ms 2 9780 Escape velocity kms 11186 GM x 10 6 km 3 s 2 039860 Bond. Earth radius denoted by the symbol R or by is the distance from the center of Earth to a point on or near its surface. 9 Estimating the Earths Density 91 Introduction We know based upon a variety of measurement methods that the density of the Earth is 552 grams per cubic centimeter.

Using the volumetric radius of the Earth 6371010 6 m this function evaluates to a total Earth mass of 5972710 24 kg. R km 0 800 1200 1400 2000 3000 ρ kgm3 13000 12900 12700 12000 11650 10600 r km 3400 3600 4000 5000 5500 6370 ρ kgm3 9900 5500 5300 4750 4500 3300 The mass of the Earth can be calculated from m Z 6370 0 4πr2 ρdr. The earth has a radius of approximately 6300 kilometers.

Planets A and B have same average density. The earth is denser near its core. Equation for the volume of the sphere.

Texg - fracGr2int_V rhodVtex. The density ρ of the Earth varies with the radius r according to the following table. 800 r km p kgm³ 1200 1400 2000 3000 12700 12000 11650 10600 13000 12900 3400 3600 4000 5000 5500 6370 5300 4750 4500 3300 9900 5500 r km p kgm³ The mass of the Earth can be calculated from 6370 4πr².

We work with density models specified as a sequence of values ρz at successive depth points z r e-r where the radius of the Earth r e 6371 km. 3 Thats very close given that the PREM densities were inferred from the speed of sound within the Earth using seismographic data. Are we able to measure the mass density and radius of super earths yet.

The gravitational field strength at the surface is g. When n_0 is the density at the earth surface rR_e then the density at radius r is given by nrn_0exp-fracErkT where the potential energy Er of an air molecule with mass m at radius r with respect to the surface radius R_e is Er-fracGM_EmrfracGM_EmR_e-GM_Emfrac1r-frac1R_e Thus the air mass. The values dN and dE are distances in the surface of the sphere.

Show that if the earth consisted of a mantle of density 4500 kgm3 and thickness ra2 and a core of density 12500 kgm3 of thickness r a2 that the total mass and average density would be equal to that of a homogeneous sphere of radius ra and density 5500 kgm3 throughout. The equation for calculating the volume of a spherical shell takes both of these radii into account. New comments cannot be posted and votes cannot be cast.

Even though the earth is not exactly a sphere but it is close enough. A 6378 km and rc 3486 km. Radius of A is twice that of B The ratio of acceleration due to gravity on the surface of A and B is.

Approximating the figure of Earth by an Earth spheroid the radius ranges from a maximum of nearly 6378 km 3963 mi equatorial radius denoted a to a minimum of nearly 6357 km 3950 mi polar radius denoted b. Super Earth Mass Density Radius. Given the average density of rocks at the Earths surface and profiles of the P-wave and S-wave.

Density of Earth as a function of depth Each layer of Earth has a specific density. This is only 0015 lower than the NASA figure of 5973610 24 kg. Fine the Center and Radius of the Circle given that it equation is x2 y2 2x -6y - 6 0.

The average density of the earth MassVolume. Mass of the earth 5971024kg. For an ellipsoidal earth t here is a different radius for each of the directions.

BeginarraylV frac43times pi times r3endarray Let us consider. The radius of the earth r 637106m. However rocks found at the surface of Earth.

Ask an expert Ask an expert done loading. View Density-as-a-function-of-radius-in-the-Earths-mantle-15_Q320jpg from SCIENCE 305 at University of British Columbia. The average density of the earth in terms of gG and R is.

VOLUME 43 π RADIUS3. The AdamsWilliamson equation named after Leason H. Mechanical Engineering questions and answers.

For a constant density we have a volume V 4 3 π r 3 thus mass M ρ 1 V and the gravity is given as g r G M r 2 G 4 3 π r ρ 1 linear like you found. Show that if the Earth consisted of a mantle of density 4500 kgm3and thickness ra2 and a core of density 12500 kgm3of thickness r. Density radius and g 9 Answers The earth has density rho p and radius R.

Calculate CMR2 for the equal thickness model in c above. The density p of the Earth varies with the radius r according to the following table. A2 that the total mass and average density would be equal to that of a homogeneous sphere of radius raand density 5500 kgm3 throughout.

Williamson is an equation used to determine density as a function of radius more commonly used to determine the relation between the velocities of seismic waves and the density of the Earths interior. This thread is archived. If you allow the density to vary then things get a lot more complicated.

Suppose that the density of the earth was given by rhor-00016r13 where r has units of kilometers and rho is in trillions of kilograms per cubic kilometer in more normal units 1 text trillion frackgkm31 fracgcm3. Thus combining your knowledge of the mass M underneath you and the radius r towards the center of this planet you can compute the gravity field using the equation you give. In rectangular coordinates the density is a function of position.

Show that if the Earth consisted of a mantle of density 4500 kgm3 and thickness ra2 and a core of density 12500 kgm3 of thickness r a2 that the total mass and average density would be equal to that of a homogeneous sphere of radius ra and density 5500 kgm3 throughout. Radius as shown below. For two layers it is a sum of this.

Density As A Function Of Radius In The Earth S Mantle 15 Download Scientific Diagram